2x+(4x^2+3x-2)^1/2

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Solution for 2x+(4x^2+3x-2)^1/2 equation: 


x in (-oo:+oo)

((4*x^2+3*x-2)^1)/2+2*x = 0

(4*x^2+3*x-2)/2+2*x = 0

(4*x^2+3*x-2)/2+(2*2*x)/2 = 0

4*x^2+3*x+2*2*x-2 = 0

4*x^2+7*x-2 = 0

4*x^2+7*x-2 = 0

4*x^2+7*x-2 = 0

DELTA = 7^2-(-2*4*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-7)/(2*4) or x = (-81^(1/2)-7)/(2*4)

x = 1/4 or x = -2

(x+2)*(x-1/4) = 0

((x+2)*(x-1/4))/2 = 0

((x+2)*(x-1/4))/2 = 0 // * 2

(x+2)*(x-1/4) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-1/4 )

x-1/4 = 0 // + 1/4

x = 1/4

x in { -2, 1/4 }

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